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  • C#学习13————枚举的类型转换

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QQstate state = QQstate.Online;
//  枚举类型默认可与int类型互相转换 枚举类型和int类型是兼容的
//  通过强制转换进行转换


//  枚举类型转int类型
int n = (int)state;
Console.WriteLine(n);

//   #region可以将写好的一个模块隐藏起来,清晰界面

#region 写了一个5,并显示
int number = 5;
Console.WriteLine(number);
#endregion


//  int类型转枚举类型
int n2 = 3;
Season season = (Season)n2;
Console.WriteLine(season);


// 所有的类型都能转换为string类型
int n3 = 10;
string s = n3.ToString();
decimal d = 5000m;
string s2 = d.ToString();
Console.WriteLine(s);
Console.WriteLine(d);


//  枚举与字符串的转换
QQstate state2 = QQstate.QMe;
string s3 = state2.ToString();
Console.WriteLine(s3);

//  字符串转换为枚举
string s4 = "3";    //or   string s4="Winter";
//调用parse帮助我们将字符串转换为对应的枚举类型;
//
Season season2= (Season)Enum.Parse(typeof(Season), s4);
Console.WriteLine(season2);





public enum QQstate
{
    //枚举的int类型默认从0开始;
    Online,
    Basy,
    Offline,
    Leave,
    QMe
}

public enum Season
{
    //在这个枚举中的默认转换则从4开始
    Spring=3,
    Summer,
    Autumn,
    Winter
}
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//用户输入数字,程序显示对应状态
#region  第一种方法
bool b = true;
while (b)
{
    Console.WriteLine("请输入您的QQ状态:1-Online;2-Offline;3-basy;4-leave;5-QMe");
    string State = Console.ReadLine();

    switch (State)
    {
        case "1":
            QQstate state = (QQstate)Enum.Parse(typeof(QQstate), State);
            Console.WriteLine(state);
            b = false;
            break;
        case "2":
            QQstate state2 = (QQstate)Enum.Parse(typeof(QQstate), State);
            Console.WriteLine(state2);
            b = false;
            break;
        case "3":
            QQstate state3 = (QQstate)Enum.Parse(typeof(QQstate), State);
            Console.WriteLine(state3);
            b = false;
            break;
        case "4":
            QQstate state4 = (QQstate)Enum.Parse(typeof(QQstate), State);
            Console.WriteLine(state4);
            b = false;
            break;
        case "5":
            QQstate state5 = (QQstate)Enum.Parse(typeof(QQstate), State);
            Console.WriteLine(state5);
            b = false;
            break;
        default:
            Console.WriteLine("输入有误,请重新输入");
            break;
    }
}
#endregion
//   思考:如果是直接转化的话可以考虑去除switch结构,直接进行转化,并添加try、catch与循环保证程序稳定正常运行
//下面这种方法的漏洞在于输入数字时转化失败并不报错,所以成功的还是上一种

bool bo = true;
while (bo)
{
    try
    {
        Console.WriteLine("请输入您的QQ状态:1-Online;2-Offline;3-basy;4-leave;5-QMe");


        string State_levelup = Console.ReadLine();
        QQstate state_levelup = (QQstate)Enum.Parse(typeof(QQstate), State_levelup);
        
        Console.WriteLine(state_levelup);
        bo = false;
    }
    catch
    {
        Console.WriteLine("输入有误请重新输入");
    }
}
public enum QQstate
{
    Online=1,
    Offline,
    Basy,
    Leave,
    QMe
}
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原文链接:https://www.cnblogs.com/interesters-together/p/15988164.html


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